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6.
Process or Product Monitoring and Control
6.6. Case Studies in Process Monitoring 6.6.2. Aerosol Particle Size
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| Residuals |
After fitting the model, we should check whether the model is
appropriate.
As with standard non-linear least squares fitting, the primary tool for model diagnostic checking is residual analysis. |
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| 4-Plot of Residuals from ARIMA(2,1,0) Model |
The 4-plot
is a convenient graphical technique for model validation in that it tests
the assumptions for the residuals on a single graph.
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| Interpretation of the 4-Plot |
We can make the following conclusions based on the above 4-plot.
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| Autocorrelation Plot of Residuals from ARIMA(2,1,0) Model |
In addition, the
autocorrelation plot
of the residuals from the ARIMA(2,1,0) model was generated.
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| Interpretation of the Autocorrelation Plot | The autocorrelation plot shows that for the first 25 lags, all sample autocorrelations expect those at lags 7 and 18 fall inside the 95% confidence bounds indicating the residuals appear to be random. | ||
| Ljung-Box Test for Randomness for the ARIMA(2,1,0) Model |
Instead of checking the autocorrelation of the residuals, portmanteau
tests such as the test proposed by
Ljung and Box (1978) can
be used. In this example, the test of Ljung and Box indicates that
the residuals are random at the 95% confidence level and thus the
model is appropriate. Dataplot generated the following output
for the Ljung-Box test.
LJUNG-BOX TEST FOR RANDOMNESS
1. STATISTICS:
NUMBER OF OBSERVATIONS = 559
LAG TESTED = 24
LAG 1 AUTOCORRELATION = -0.1012441E-02
LAG 2 AUTOCORRELATION = 0.6160716E-02
LAG 3 AUTOCORRELATION = 0.5182213E-02
LJUNG-BOX TEST STATISTIC = 31.91066
2. PERCENT POINTS OF THE REFERENCE CHI-SQUARE DISTRIBUTION
(REJECT HYPOTHESIS OF RANDOMNESS IF TEST STATISTIC VALUE
IS GREATER THAN PERCENT POINT VALUE)
FOR LJUNG-BOX TEST STATISTIC
0 % POINT = 0.
50 % POINT = 23.33673
75 % POINT = 28.24115
90 % POINT = 33.19624
95 % POINT = 36.41503
99 % POINT = 42.97982
3. CONCLUSION (AT THE 5% LEVEL):
THE DATA ARE RANDOM.
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| 4-Plot of Residuals from ARIMA(0,1,1) Model |
The 4-plot
is a convenient graphical technique for model validation in that it tests
the assumptions for the residuals on a single graph.
|
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| Interpretation of the 4-Plot from the ARIMA(0,1,1) Model |
We can make the following conclusions based on the above 4-plot.
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| Autocorrelation Plot of Residuals from ARIMA(0,1,1) Model |
The autocorrelation plot of the residuals from ARIMA(0,1,1) was
generated.
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| Interpretation of the Autocorrelation Plot | Similar to the result for the ARIMA(2,1,0) model, it shows that for the first 25 lags, all sample autocorrelations expect those at lags 7 and 18 fall inside the 95% confidence bounds indicating the residuals appear to be random. | ||
| Ljung-Box Test for Randomness of the Residuals for the ARIMA(0,1,1) Model |
The Ljung and Box test is also applied to the residuals from the
ARIMA(0,1,1) model. The test indicates that the residuals are random
at the 99% confidence level, but not at the 95% level.
Dataplot generated the following output for the Ljung-Box test.
LJUNG-BOX TEST FOR RANDOMNESS
1. STATISTICS:
NUMBER OF OBSERVATIONS = 559
LAG TESTED = 24
LAG 1 AUTOCORRELATION = -0.1280136E-01
LAG 2 AUTOCORRELATION = -0.3764571E-02
LAG 3 AUTOCORRELATION = 0.7015200E-01
LJUNG-BOX TEST STATISTIC = 38.76418
2. PERCENT POINTS OF THE REFERENCE CHI-SQUARE DISTRIBUTION
(REJECT HYPOTHESIS OF RANDOMNESS IF TEST STATISTIC VALUE
IS GREATER THAN PERCENT POINT VALUE)
FOR LJUNG-BOX TEST STATISTIC
0 % POINT = 0.
50 % POINT = 23.33673
75 % POINT = 28.24115
90 % POINT = 33.19624
95 % POINT = 36.41503
99 % POINT = 42.97982
3. CONCLUSION (AT THE 5% LEVEL):
THE DATA ARE NOT RANDOM.
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| Summary | Overall, the ARIMA(0,1,1) is an adequate model. However, the ARIMA(2,1,0) is a little better than the ARIMA(0,1,1). | ||