7. Product and Process Comparisons
7.2. Comparisons based on data from one process
7.2.4. Does the proportion of defectives meet requirements?

7.2.4.2.

Sample sizes required

Derivation of formula for required sample size when testing proportions

The method of determining sample sizes for testing proportions is similar to the method for determining sample sizes for testing the mean. Although the sampling distribution for proportions actually follows a binomial distribution, the normal approximation is used for this derivation.

Problem formulation

We want to test the hypothesis

H₀: p = p₀
H_a: p ≠ p₀

with p denoting the proportion of defectives.

Define as the change in the proportion defective that we are interested in detecting

= |p₁ - p₀|

Specify the level of statisitical significance and statistical power, respectively, by

P(reject H₀ | H₀ is true with any p ≠ p₀) ≤
P(reject H₀ | H₀ is false with any p ≤ ) ≤ 1 -

Definition of allowable deviation

If we are interested in detecting a change in the proportion defective of size in either direction, the corresponding confidence interval for p can be written

Relationship to confidence interval

For a (1-)% confidence interval based on the normal distribution, where is the upper critical value of the normal distribution which is exceeded with probability ,

Minimum sample size

Thus, the minimum sample size is

1. For a two-sided interval

   
   
   

2. For a one-sided interval

   
   

   The mathematical details of this derivation are given on pages 30-34 of Fleiss, Levin, and Paik.

Continuity correction

Fleiss, Levin and Paik also recommend the following continuity correction

N = N' + 1/

with N' denoting the sample size computed using the above formula.

Example of calculating sample size for testing proportion defective

Suppose that a department manager needs to be able to detect any change above 0.10 in the current proportion defective of his product line, which is running at approximately 10% defective. He is interested in a one-sided test and does not want to stop the line except when the process has clearly degraded and, therefore, he chooses a significance level for the test of 5%. Suppose, also, that he is willing to take a risk of 10% of failing to detect a change of this magnitude. With these criteria:

1. z_.05 = 1.645; z_.10=1.282
2. = 0.10 (p₁ = 0.20)
3. p₀ = 0.10

and the minimum sample size for a one-sided test procedure is

With the continuity correction, the minimum sample size becomes 112.