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7.
Product and Process Comparisons
7.4. Comparisons based on data from more than two processes 7.4.3. Are the means equal?
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| Basic Layout | |||||||||||||||||||||||||||||||||||||||||||||||||||||||
| The balanced 2-way factorial layout |
Factor A has 1, 2, ..., a levels. Factor B has 1, 2, ...,
b levels. There are ab treatment combinations (or
cells) in a complete factorial layout. Assume that each treatment
cell has r independent obsevations (known as replications).
When each cell has the same number of replications, the design is
a balanced factorial. In this case, the abrdata points
{yijk} can be shown pictorially as follows:
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| How to obtain sums of squares for the balanced factorial layout |
Next, we will calculate the sums of squares needed for the ANOVA
table.
Finally, the total number of observations n in the experiment is abr. With the help of these expressions we arrive (omitting derivations) at
These expressions are used to calculate the ANOVA table entries for the (fixed effects) 2-way ANOVA. |
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| Two-Way ANOVA Example: | |||||||||||||||||||||||||||||||||||||||||||||||||||||||
| Data |
An evaluation of a new coating applied to 3 different materials was
conducted at 2 different laboratories. Each laboratory tested 3
samples from each of the treated materials. The results are given
in the next table:
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| Row and column sums |
The preliminary part of the analysis yields a table of row and
column sums.
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| ANOVA table |
From this table we generate the ANOVA table.
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